Base | Representation |
---|---|
bin | 1000011100111101110… |
… | …1001010100000011011 |
3 | 111212211020121100222112 |
4 | 2013033131022200123 |
5 | 4334344344342231 |
6 | 150413253342535 |
7 | 13330356312353 |
oct | 2071735124033 |
9 | 455736540875 |
10 | 145214449691 |
11 | 566488533a3 |
12 | 24188037a4b |
13 | 10902c96b9c |
14 | 7057d93b63 |
15 | 3b9d8d892b |
hex | 21cf74a81b |
145214449691 has 2 divisors, whose sum is σ = 145214449692. Its totient is φ = 145214449690.
The previous prime is 145214449673. The next prime is 145214449717. The reversal of 145214449691 is 196944412541.
145214449691 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (196944412541) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 145214449691 - 214 = 145214433307 is a prime.
It is not a weakly prime, because it can be changed into another prime (145214479691) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72607224845 + 72607224846.
It is an arithmetic number, because the mean of its divisors is an integer number (72607224846).
Almost surely, 2145214449691 is an apocalyptic number.
145214449691 is a deficient number, since it is larger than the sum of its proper divisors (1).
145214449691 is an equidigital number, since it uses as much as digits as its factorization.
145214449691 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1244160, while the sum is 50.
The spelling of 145214449691 in words is "one hundred forty-five billion, two hundred fourteen million, four hundred forty-nine thousand, six hundred ninety-one".
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