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145222412320537 is a prime number
BaseRepresentation
bin100001000001010000111010…
…010011001011111100011001
3201001012010102121101012102121
4201001100322103023330121
5123013311000023224122
61232510131043301241
742405654520421506
oct4101207223137431
9631163377335377
10145222412320537
11422aa52a8a6062
12143550b007a821
1363055511ac256
1427c0b335864ad
1511bc87caa9bc7
hex84143a4cbf19

145222412320537 has 2 divisors, whose sum is σ = 145222412320538. Its totient is φ = 145222412320536.

The previous prime is 145222412320519. The next prime is 145222412320543. The reversal of 145222412320537 is 735023214222541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134000743105161 + 11221669215376 = 11575869^2 + 3349876^2 .

It is a cyclic number.

It is not a de Polignac number, because 145222412320537 - 235 = 145188052582169 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 145222412320493 and 145222412320502.

It is not a weakly prime, because it can be changed into another prime (145222412320507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72611206160268 + 72611206160269.

It is an arithmetic number, because the mean of its divisors is an integer number (72611206160269).

Almost surely, 2145222412320537 is an apocalyptic number.

It is an amenable number.

145222412320537 is a deficient number, since it is larger than the sum of its proper divisors (1).

145222412320537 is an equidigital number, since it uses as much as digits as its factorization.

145222412320537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 806400, while the sum is 43.

The spelling of 145222412320537 in words is "one hundred forty-five trillion, two hundred twenty-two billion, four hundred twelve million, three hundred twenty thousand, five hundred thirty-seven".