Base | Representation |
---|---|
bin | 1000011100111111111… |
… | …0111110001100000011 |
3 | 111212211212021121222001 |
4 | 2013033332332030003 |
5 | 4334404131442011 |
6 | 150414211324431 |
7 | 13330524533362 |
oct | 2071776761403 |
9 | 455755247861 |
10 | 145223312131 |
11 | 56652856927 |
12 | 2418abb0717 |
13 | 10904a7aa31 |
14 | 705921d7d9 |
15 | 3b9e5897c1 |
hex | 21cffbe303 |
145223312131 has 2 divisors, whose sum is σ = 145223312132. Its totient is φ = 145223312130.
The previous prime is 145223312111. The next prime is 145223312153. The reversal of 145223312131 is 131213322541.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 145223312131 - 25 = 145223312099 is a prime.
It is a super-2 number, since 2×1452233121312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 145223312131.
It is not a weakly prime, because it can be changed into another prime (145223312111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72611656065 + 72611656066.
It is an arithmetic number, because the mean of its divisors is an integer number (72611656066).
Almost surely, 2145223312131 is an apocalyptic number.
145223312131 is a deficient number, since it is larger than the sum of its proper divisors (1).
145223312131 is an equidigital number, since it uses as much as digits as its factorization.
145223312131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4320, while the sum is 28.
Adding to 145223312131 its reverse (131213322541), we get a palindrome (276436634672).
The spelling of 145223312131 in words is "one hundred forty-five billion, two hundred twenty-three million, three hundred twelve thousand, one hundred thirty-one".
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