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145223312131 is a prime number
BaseRepresentation
bin1000011100111111111…
…0111110001100000011
3111212211212021121222001
42013033332332030003
54334404131442011
6150414211324431
713330524533362
oct2071776761403
9455755247861
10145223312131
1156652856927
122418abb0717
1310904a7aa31
14705921d7d9
153b9e5897c1
hex21cffbe303

145223312131 has 2 divisors, whose sum is σ = 145223312132. Its totient is φ = 145223312130.

The previous prime is 145223312111. The next prime is 145223312153. The reversal of 145223312131 is 131213322541.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 145223312131 - 25 = 145223312099 is a prime.

It is a super-2 number, since 2×1452233121312 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 145223312131.

It is not a weakly prime, because it can be changed into another prime (145223312111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72611656065 + 72611656066.

It is an arithmetic number, because the mean of its divisors is an integer number (72611656066).

Almost surely, 2145223312131 is an apocalyptic number.

145223312131 is a deficient number, since it is larger than the sum of its proper divisors (1).

145223312131 is an equidigital number, since it uses as much as digits as its factorization.

145223312131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4320, while the sum is 28.

Adding to 145223312131 its reverse (131213322541), we get a palindrome (276436634672).

The spelling of 145223312131 in words is "one hundred forty-five billion, two hundred twenty-three million, three hundred twelve thousand, one hundred thirty-one".