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14523465113 = 26237553549
BaseRepresentation
bin11011000011010101…
…00111110110011001
31101111011110110201022
431201222213312121
5214221001340423
610401052132225
71022622262613
oct154152476631
941434413638
1014523465113
116183132333
122993a67075
1314a5bbb651
149bac19db3
155a0083dc8
hex361aa7d99

14523465113 has 4 divisors (see below), whose sum is σ = 14524044900. Its totient is φ = 14522885328.

The previous prime is 14523465101. The next prime is 14523465191. The reversal of 14523465113 is 31156432541.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6157070089 + 8366395024 = 78467^2 + 91468^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14523465113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14523465013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 250538 + ... + 303011.

It is an arithmetic number, because the mean of its divisors is an integer number (3631011225).

Almost surely, 214523465113 is an apocalyptic number.

It is an amenable number.

14523465113 is a deficient number, since it is larger than the sum of its proper divisors (579787).

14523465113 is an equidigital number, since it uses as much as digits as its factorization.

14523465113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 579786.

The product of its digits is 43200, while the sum is 35.

Adding to 14523465113 its reverse (31156432541), we get a palindrome (45679897654).

The spelling of 14523465113 in words is "fourteen billion, five hundred twenty-three million, four hundred sixty-five thousand, one hundred thirteen".

Divisors: 1 26237 553549 14523465113