145254031411 has 4 divisors (see below), whose sum is σ = 145466702712. Its totient is φ = 145041360112.

The previous prime is 145254031409. The next prime is 145254031423. The reversal of 145254031411 is 114130452541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145254031411 - 2¹ = 145254031409 is a prime.

It is a super-2 number, since 2×145254031411² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (145254034411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106334626 + ... + 106335991.

It is an arithmetic number, because the mean of its divisors is an integer number (36366675678).

Almost surely, 2^145254031411 is an apocalyptic number.

145254031411 is a deficient number, since it is larger than the sum of its proper divisors (212671301).

145254031411 is an equidigital number, since it uses as much as digits as its factorization.

145254031411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 212671300.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 145254031411 its reverse (114130452541), we get a palindrome (259384483952).

The spelling of 145254031411 in words is "one hundred forty-five billion, two hundred fifty-four million, thirty-one thousand, four hundred eleven".