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14525405203 = 374327313343
BaseRepresentation
bin11011000011100100…
…00001100000010011
31101111022010001000111
431201302001200103
5214222000431303
610401201502151
71022644623061
oct154162014023
941438101014
1014525405203
116184237a11
122994641957
1314a641a72a
149bb1a3031
155a0318b6d
hex361c81813

14525405203 has 16 divisors (see below), whose sum is σ = 15275070976. Its totient is φ = 13794973920.

The previous prime is 14525405179. The next prime is 14525405207. The reversal of 14525405203 is 30250452541.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14525405203 is a prime.

It is a super-2 number, since 2×145254052032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14525405207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4343350 + ... + 4346692.

It is an arithmetic number, because the mean of its divisors is an integer number (954691936).

Almost surely, 214525405203 is an apocalyptic number.

14525405203 is a deficient number, since it is larger than the sum of its proper divisors (749665773).

14525405203 is a wasteful number, since it uses less digits than its factorization.

14525405203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6154.

The product of its (nonzero) digits is 24000, while the sum is 31.

Adding to 14525405203 its reverse (30250452541), we get a palindrome (44775857744).

The spelling of 14525405203 in words is "fourteen billion, five hundred twenty-five million, four hundred five thousand, two hundred three".

Divisors: 1 37 43 1591 2731 3343 101047 117433 123691 143749 4345021 5318713 9129733 337800121 392578519 14525405203