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145254510131 is a prime number
BaseRepresentation
bin1000011101000111010…
…1111110111000110011
3111212221000222122120112
42013101311332320303
54334440123311011
6150421244131535
713331353651553
oct2072165767063
9455830878515
10145254510131
11566694253a5
1224199536bab
131090b3820a3
14705d421163
153ba219d58b
hex21d1d7ee33

145254510131 has 2 divisors, whose sum is σ = 145254510132. Its totient is φ = 145254510130.

The previous prime is 145254510073. The next prime is 145254510139. The reversal of 145254510131 is 131015452541.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145254510131 is a prime.

It is a super-2 number, since 2×1452545101312 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145254510139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72627255065 + 72627255066.

It is an arithmetic number, because the mean of its divisors is an integer number (72627255066).

Almost surely, 2145254510131 is an apocalyptic number.

145254510131 is a deficient number, since it is larger than the sum of its proper divisors (1).

145254510131 is an equidigital number, since it uses as much as digits as its factorization.

145254510131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 145254510131 its reverse (131015452541), we get a palindrome (276269962672).

The spelling of 145254510131 in words is "one hundred forty-five billion, two hundred fifty-four million, five hundred ten thousand, one hundred thirty-one".