Base | Representation |
---|---|
bin | 1000011101000111010… |
… | …1111110111000110011 |
3 | 111212221000222122120112 |
4 | 2013101311332320303 |
5 | 4334440123311011 |
6 | 150421244131535 |
7 | 13331353651553 |
oct | 2072165767063 |
9 | 455830878515 |
10 | 145254510131 |
11 | 566694253a5 |
12 | 24199536bab |
13 | 1090b3820a3 |
14 | 705d421163 |
15 | 3ba219d58b |
hex | 21d1d7ee33 |
145254510131 has 2 divisors, whose sum is σ = 145254510132. Its totient is φ = 145254510130.
The previous prime is 145254510073. The next prime is 145254510139. The reversal of 145254510131 is 131015452541.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-145254510131 is a prime.
It is a super-2 number, since 2×1452545101312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (145254510139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72627255065 + 72627255066.
It is an arithmetic number, because the mean of its divisors is an integer number (72627255066).
Almost surely, 2145254510131 is an apocalyptic number.
145254510131 is a deficient number, since it is larger than the sum of its proper divisors (1).
145254510131 is an equidigital number, since it uses as much as digits as its factorization.
145254510131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 145254510131 its reverse (131015452541), we get a palindrome (276269962672).
The spelling of 145254510131 in words is "one hundred forty-five billion, two hundred fifty-four million, five hundred ten thousand, one hundred thirty-one".
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