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145300254361 is a prime number
BaseRepresentation
bin1000011101010010010…
…0011110111010011001
3111220001020001200212021
42013110210132322121
54340033331114421
6150430000414441
713332450532633
oct2072444367231
9456036050767
10145300254361
1156692229749
12241b0917421
13109179aa392
14706552ba53
153ba61d7341
hex21d491ee99

145300254361 has 2 divisors, whose sum is σ = 145300254362. Its totient is φ = 145300254360.

The previous prime is 145300254347. The next prime is 145300254373. The reversal of 145300254361 is 163452003541.

145300254361 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 145298954761 + 1299600 = 381181^2 + 1140^2 .

It is a cyclic number.

It is not a de Polignac number, because 145300254361 - 215 = 145300221593 is a prime.

It is a super-2 number, since 2×1453002543612 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145300254061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72650127180 + 72650127181.

It is an arithmetic number, because the mean of its divisors is an integer number (72650127181).

Almost surely, 2145300254361 is an apocalyptic number.

It is an amenable number.

145300254361 is a deficient number, since it is larger than the sum of its proper divisors (1).

145300254361 is an equidigital number, since it uses as much as digits as its factorization.

145300254361 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 34.

The spelling of 145300254361 in words is "one hundred forty-five billion, three hundred million, two hundred fifty-four thousand, three hundred sixty-one".