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14530054051 = 312332011637
BaseRepresentation
bin11011000100000111…
…10000011110100011
31101111121212020001001
431202003300132203
5214224143212201
610401445252431
71023032264422
oct154203603643
941447766031
1014530054051
116186922737
122996104117
1314a7387726
149bba532b9
155a0936301
hex3620f07a3

14530054051 has 8 divisors (see below), whose sum is σ = 15063145344. Its totient is φ = 14000986560.

The previous prime is 14530053997. The next prime is 14530054081. The reversal of 14530054051 is 15045003541.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14530054051 - 223 = 14521665443 is a prime.

It is a super-2 number, since 2×145300540512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14530054081) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 998596 + ... + 1013041.

It is an arithmetic number, because the mean of its divisors is an integer number (1882893168).

Almost surely, 214530054051 is an apocalyptic number.

14530054051 is a deficient number, since it is larger than the sum of its proper divisors (533091293).

14530054051 is a wasteful number, since it uses less digits than its factorization.

14530054051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2011901.

The product of its (nonzero) digits is 6000, while the sum is 28.

Adding to 14530054051 its reverse (15045003541), we get a palindrome (29575057592).

The spelling of 14530054051 in words is "fourteen billion, five hundred thirty million, fifty-four thousand, fifty-one".

Divisors: 1 31 233 7223 2011637 62360747 468711421 14530054051