Base | Representation |
---|---|
bin | 11011000100001000… |
… | …00001110101000001 |
3 | 1101111121222211112021 |
4 | 31202010001311001 |
5 | 214224203000441 |
6 | 10401451001441 |
7 | 1023033011551 |
oct | 154204016501 |
9 | 41447884467 |
10 | 14530125121 |
11 | 6186971076 |
12 | 2996139281 |
13 | 14a73b0b95 |
14 | 9bba71161 |
15 | 5a094c3d1 |
hex | 362101d41 |
14530125121 has 4 divisors (see below), whose sum is σ = 14534490544. Its totient is φ = 14525759700.
The previous prime is 14530125109. The next prime is 14530125161. The reversal of 14530125121 is 12152103541.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14530125121 - 27 = 14530124993 is a prime.
It is a super-2 number, since 2×145301251212 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14530125101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2177715 + ... + 2184376.
It is an arithmetic number, because the mean of its divisors is an integer number (3633622636).
Almost surely, 214530125121 is an apocalyptic number.
It is an amenable number.
14530125121 is a deficient number, since it is larger than the sum of its proper divisors (4365423).
14530125121 is an equidigital number, since it uses as much as digits as its factorization.
14530125121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4365422.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 14530125121 its reverse (12152103541), we get a palindrome (26682228662).
The spelling of 14530125121 in words is "fourteen billion, five hundred thirty million, one hundred twenty-five thousand, one hundred twenty-one".
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