Base | Representation |
---|---|
bin | 11011000100001000… |
… | …10010101110101011 |
3 | 1101111122010100111012 |
4 | 31202010102232223 |
5 | 214224212204342 |
6 | 10401452254135 |
7 | 1023033420434 |
oct | 154204225653 |
9 | 41448110435 |
10 | 14530194347 |
11 | 6186a09089 |
12 | 299617134b |
13 | 14a7406546 |
14 | 9bba8c48b |
15 | 5a0962b82 |
hex | 362112bab |
14530194347 has 2 divisors, whose sum is σ = 14530194348. Its totient is φ = 14530194346.
The previous prime is 14530194331. The next prime is 14530194359. The reversal of 14530194347 is 74349103541.
It is a strong prime.
It is an emirp because it is prime and its reverse (74349103541) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14530194347 - 24 = 14530194331 is a prime.
It is a super-2 number, since 2×145301943472 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14530194397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7265097173 + 7265097174.
It is an arithmetic number, because the mean of its divisors is an integer number (7265097174).
Almost surely, 214530194347 is an apocalyptic number.
14530194347 is a deficient number, since it is larger than the sum of its proper divisors (1).
14530194347 is an equidigital number, since it uses as much as digits as its factorization.
14530194347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 181440, while the sum is 41.
Adding to 14530194347 its reverse (74349103541), we get a palindrome (88879297888).
The spelling of 14530194347 in words is "fourteen billion, five hundred thirty million, one hundred ninety-four thousand, three hundred forty-seven".
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