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1453266606457 is a prime number
BaseRepresentation
bin10101001001011101011…
…100001001100101111001
312010221010122111202202001
4111021131130021211321
5142302242222401312
63031342122541001
7206665205223541
oct25113534114571
95127118452661
101453266606457
115103661270a6
121b57a0067761
13a7072366413
14504a4b02321
1527c096ad057
hex1525d709979

1453266606457 has 2 divisors, whose sum is σ = 1453266606458. Its totient is φ = 1453266606456.

The previous prime is 1453266606437. The next prime is 1453266606497. The reversal of 1453266606457 is 7546066623541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1009902393721 + 443364212736 = 1004939^2 + 665856^2 .

It is a cyclic number.

It is not a de Polignac number, because 1453266606457 - 223 = 1453258217849 is a prime.

It is a super-2 number, since 2×14532666064572 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1453266606398 and 1453266606407.

It is not a weakly prime, because it can be changed into another prime (1453266606437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726633303228 + 726633303229.

It is an arithmetic number, because the mean of its divisors is an integer number (726633303229).

Almost surely, 21453266606457 is an apocalyptic number.

It is an amenable number.

1453266606457 is a deficient number, since it is larger than the sum of its proper divisors (1).

1453266606457 is an equidigital number, since it uses as much as digits as its factorization.

1453266606457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21772800, while the sum is 55.

The spelling of 1453266606457 in words is "one trillion, four hundred fifty-three billion, two hundred sixty-six million, six hundred six thousand, four hundred fifty-seven".