Base | Representation |
---|---|
bin | 11011000100100110… |
… | …01100011001110001 |
3 | 1101111220110210211222 |
4 | 31202103030121301 |
5 | 214231212204333 |
6 | 10402112114425 |
7 | 1023111550055 |
oct | 154223143161 |
9 | 41456423758 |
10 | 14534100593 |
11 | 6189136991 |
12 | 2997535a15 |
13 | 14a817352c |
14 | 9bc3c7c65 |
15 | 5a0e85298 |
hex | 3624cc671 |
14534100593 has 2 divisors, whose sum is σ = 14534100594. Its totient is φ = 14534100592.
The previous prime is 14534100583. The next prime is 14534100611. The reversal of 14534100593 is 39500143541.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14434340449 + 99760144 = 120143^2 + 9988^2 .
It is a cyclic number.
It is not a de Polignac number, because 14534100593 - 216 = 14534035057 is a prime.
It is a super-2 number, since 2×145341005932 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14534100583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7267050296 + 7267050297.
It is an arithmetic number, because the mean of its divisors is an integer number (7267050297).
Almost surely, 214534100593 is an apocalyptic number.
It is an amenable number.
14534100593 is a deficient number, since it is larger than the sum of its proper divisors (1).
14534100593 is an equidigital number, since it uses as much as digits as its factorization.
14534100593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 35.
The spelling of 14534100593 in words is "fourteen billion, five hundred thirty-four million, one hundred thousand, five hundred ninety-three".
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