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14534100593 is a prime number
BaseRepresentation
bin11011000100100110…
…01100011001110001
31101111220110210211222
431202103030121301
5214231212204333
610402112114425
71023111550055
oct154223143161
941456423758
1014534100593
116189136991
122997535a15
1314a817352c
149bc3c7c65
155a0e85298
hex3624cc671

14534100593 has 2 divisors, whose sum is σ = 14534100594. Its totient is φ = 14534100592.

The previous prime is 14534100583. The next prime is 14534100611. The reversal of 14534100593 is 39500143541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14434340449 + 99760144 = 120143^2 + 9988^2 .

It is a cyclic number.

It is not a de Polignac number, because 14534100593 - 216 = 14534035057 is a prime.

It is a super-2 number, since 2×145341005932 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14534100583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7267050296 + 7267050297.

It is an arithmetic number, because the mean of its divisors is an integer number (7267050297).

Almost surely, 214534100593 is an apocalyptic number.

It is an amenable number.

14534100593 is a deficient number, since it is larger than the sum of its proper divisors (1).

14534100593 is an equidigital number, since it uses as much as digits as its factorization.

14534100593 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32400, while the sum is 35.

The spelling of 14534100593 in words is "fourteen billion, five hundred thirty-four million, one hundred thousand, five hundred ninety-three".