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14534140443 = 316093011009
BaseRepresentation
bin11011000100100110…
…10110001000011011
31101111220112211111220
431202103112020123
5214231214443233
610402113023123
71023112104204
oct154223261033
941456484456
1014534140443
116189163919
122997554aa3
1314a8188704
149bc3d85ab
155a0e91eb3
hex3624d621b

14534140443 has 8 divisors (see below), whose sum is σ = 19390904400. Its totient is φ = 9683401728.

The previous prime is 14534140441. The next prime is 14534140487. The reversal of 14534140443 is 34404143541.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14534140443 - 21 = 14534140441 is a prime.

It is a super-2 number, since 2×145341404432 (a number of 21 digits) contains 22 as substring.

It is a Smith number, since the sum of its digits (33) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is not an unprimeable number, because it can be changed into a prime (14534140441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1500678 + ... + 1510331.

It is an arithmetic number, because the mean of its divisors is an integer number (2423863050).

Almost surely, 214534140443 is an apocalyptic number.

14534140443 is a deficient number, since it is larger than the sum of its proper divisors (4856763957).

14534140443 is a wasteful number, since it uses less digits than its factorization.

14534140443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3012621.

The product of its (nonzero) digits is 46080, while the sum is 33.

Adding to 14534140443 its reverse (34404143541), we get a palindrome (48938283984).

The spelling of 14534140443 in words is "fourteen billion, five hundred thirty-four million, one hundred forty thousand, four hundred forty-three".

Divisors: 1 3 1609 4827 3011009 9033027 4844713481 14534140443