Base | Representation |
---|---|
bin | 11011000101000100… |
… | …11010101010000010 |
3 | 1101112011222112211221 |
4 | 31202202122222002 |
5 | 214233222404023 |
6 | 10402333425254 |
7 | 1023160510234 |
oct | 154242325202 |
9 | 41464875757 |
10 | 14538091138 |
11 | 619041205a |
12 | 299893b22a |
13 | 14a8c3c9bc |
14 | 9bcb46254 |
15 | 5a14c285d |
hex | 36289aa82 |
14538091138 has 4 divisors (see below), whose sum is σ = 21807136710. Its totient is φ = 7269045568.
The previous prime is 14538091133. The next prime is 14538091163. The reversal of 14538091138 is 83119083541.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13211893249 + 1326197889 = 114943^2 + 36417^2 .
It is a super-2 number, since 2×145380911382 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14538091094 and 14538091103.
It is not an unprimeable number, because it can be changed into a prime (14538091133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3634522783 + ... + 3634522786.
Almost surely, 214538091138 is an apocalyptic number.
14538091138 is a deficient number, since it is larger than the sum of its proper divisors (7269045572).
14538091138 is an equidigital number, since it uses as much as digits as its factorization.
14538091138 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7269045571.
The product of its (nonzero) digits is 103680, while the sum is 43.
The spelling of 14538091138 in words is "fourteen billion, five hundred thirty-eight million, ninety-one thousand, one hundred thirty-eight".
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