Base | Representation |
---|---|
bin | 11011000101010011… |
… | …10111100010100011 |
3 | 1101112022122210021212 |
4 | 31202221313202203 |
5 | 214234222410301 |
6 | 10402443340335 |
7 | 1023213224102 |
oct | 154251674243 |
9 | 41468583255 |
10 | 14540044451 |
11 | 6191526669 |
12 | 29995216ab |
13 | 14a9474aca |
14 | 9bd0d4039 |
15 | 5a175b4bb |
hex | 362a778a3 |
14540044451 has 2 divisors, whose sum is σ = 14540044452. Its totient is φ = 14540044450.
The previous prime is 14540044423. The next prime is 14540044457. The reversal of 14540044451 is 15444004541.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14540044451 is a prime.
It is a super-2 number, since 2×145400444512 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14540044457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7270022225 + 7270022226.
It is an arithmetic number, because the mean of its divisors is an integer number (7270022226).
Almost surely, 214540044451 is an apocalyptic number.
14540044451 is a deficient number, since it is larger than the sum of its proper divisors (1).
14540044451 is an equidigital number, since it uses as much as digits as its factorization.
14540044451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25600, while the sum is 32.
Adding to 14540044451 its reverse (15444004541), we get a palindrome (29984048992).
The spelling of 14540044451 in words is "fourteen billion, five hundred forty million, forty-four thousand, four hundred fifty-one".
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