Base | Representation |
---|---|
bin | 11011000101010011… |
… | …11001111011011011 |
3 | 1101112022200021201020 |
4 | 31202221321323123 |
5 | 214234223213420 |
6 | 10402443453523 |
7 | 1023213264450 |
oct | 154251717333 |
9 | 41468607636 |
10 | 14540054235 |
11 | 6191532a53 |
12 | 29995272a3 |
13 | 14a94793b5 |
14 | 9bd0d7827 |
15 | 5a175e340 |
hex | 362a79edb |
14540054235 has 16 divisors (see below), whose sum is σ = 26587527936. Its totient is φ = 6646881888.
The previous prime is 14540054227. The next prime is 14540054239. The reversal of 14540054235 is 53245004541.
It is not a de Polignac number, because 14540054235 - 23 = 14540054227 is a prime.
It is a super-2 number, since 2×145400542352 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14540054196 and 14540054205.
It is not an unprimeable number, because it can be changed into a prime (14540054239) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 69238249 + ... + 69238458.
It is an arithmetic number, because the mean of its divisors is an integer number (1661720496).
Almost surely, 214540054235 is an apocalyptic number.
14540054235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14540054235 is a deficient number, since it is larger than the sum of its proper divisors (12047473701).
14540054235 is a wasteful number, since it uses less digits than its factorization.
14540054235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 138476722.
The product of its (nonzero) digits is 48000, while the sum is 33.
Adding to 14540054235 its reverse (53245004541), we get a palindrome (67785058776).
The spelling of 14540054235 in words is "fourteen billion, five hundred forty million, fifty-four thousand, two hundred thirty-five".
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