Base | Representation |
---|---|
bin | 10101001010010000011… |
… | …011001101111100000100 |
3 | 12011000100021002021021021 |
4 | 111022100123031330010 |
5 | 142311020213001012 |
6 | 3032003041000524 |
7 | 210025333030624 |
oct | 25122033157404 |
9 | 5130307067237 |
10 | 1454122000132 |
11 | 510764a6201a |
12 | 1b599a623144 |
13 | a717a642719 |
14 | 5054656a884 |
15 | 27c59828007 |
hex | 152906cdf04 |
1454122000132 has 6 divisors (see below), whose sum is σ = 2544713500238. Its totient is φ = 727061000064.
The previous prime is 1454122000061. The next prime is 1454122000141. The reversal of 1454122000132 is 2310002214541.
It can be written as a sum of positive squares in only one way, i.e., 1437999095556 + 16122904576 = 1199166^2 + 126976^2 .
It is a super-2 number, since 2×14541220001322 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1454122000097 and 1454122000106.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 181765250013 + ... + 181765250020.
Almost surely, 21454122000132 is an apocalyptic number.
It is an amenable number.
1454122000132 is a deficient number, since it is larger than the sum of its proper divisors (1090591500106).
1454122000132 is a wasteful number, since it uses less digits than its factorization.
1454122000132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 363530500037 (or 363530500035 counting only the distinct ones).
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 1454122000132 its reverse (2310002214541), we get a palindrome (3764124214673).
The spelling of 1454122000132 in words is "one trillion, four hundred fifty-four billion, one hundred twenty-two million, one hundred thirty-two", and thus it is an aban number.
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