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1454124245081 is a prime number
BaseRepresentation
bin10101001010010000100…
…011110010000001011001
312011000100102022022202112
4111022100203302001121
5142311021301320311
63032003201042105
7210025361100644
oct25122043620131
95130312268675
101454124245081
11510766255752
121b599b326335
13a717ac4a4b1
1450546992a5b
1527c59b1d28b
hex152908f2059

1454124245081 has 2 divisors, whose sum is σ = 1454124245082. Its totient is φ = 1454124245080.

The previous prime is 1454124245023. The next prime is 1454124245129. The reversal of 1454124245081 is 1805424214541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1126357690000 + 327766555081 = 1061300^2 + 572509^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1454124245081 is a prime.

It is a super-2 number, since 2×14541242450812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1454124245681) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 727062122540 + 727062122541.

It is an arithmetic number, because the mean of its divisors is an integer number (727062122541).

Almost surely, 21454124245081 is an apocalyptic number.

It is an amenable number.

1454124245081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1454124245081 is an equidigital number, since it uses as much as digits as its factorization.

1454124245081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 204800, while the sum is 41.

The spelling of 1454124245081 in words is "one trillion, four hundred fifty-four billion, one hundred twenty-four million, two hundred forty-five thousand, eighty-one".