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14542994833 is a prime number
BaseRepresentation
bin11011000101101010…
…00111110110010001
31101112112012200110021
431202311013312101
5214241001313313
610403030503441
71023250262563
oct154265076621
941475180407
1014542994833
1161931612a4
12299a504b81
1314a9c689b3
149bd661333
155a1b4078d
hex362d47d91

14542994833 has 2 divisors, whose sum is σ = 14542994834. Its totient is φ = 14542994832.

The previous prime is 14542994827. The next prime is 14542994887. The reversal of 14542994833 is 33849924541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14415123969 + 127870864 = 120063^2 + 11308^2 .

It is an emirp because it is prime and its reverse (33849924541) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14542994833 is a prime.

It is a super-2 number, since 2×145429948332 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14542994813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7271497416 + 7271497417.

It is an arithmetic number, because the mean of its divisors is an integer number (7271497417).

Almost surely, 214542994833 is an apocalyptic number.

It is an amenable number.

14542994833 is a deficient number, since it is larger than the sum of its proper divisors (1).

14542994833 is an equidigital number, since it uses as much as digits as its factorization.

14542994833 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3732480, while the sum is 52.

The spelling of 14542994833 in words is "fourteen billion, five hundred forty-two million, nine hundred ninety-four thousand, eight hundred thirty-three".