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145430031224154 = 23233104027204023
BaseRepresentation
bin100001000100010010010001…
…010110011100110101011010
3201001220222022220222021212110
4201010102101112130311122
5123030211200443133104
61233145344541053150
742426654514115505
oct4104222126346532
9631828286867773
10145430031224154
114237a591300316
12143893932571b6
13631bcbaabb301
1427cabcb48c13c
1511c2e7ed4be89
hex84449159cd5a

145430031224154 has 16 divisors (see below), whose sum is σ = 292108388899392. Its totient is φ = 48268622666208.

The previous prime is 145430031224131. The next prime is 145430031224161. The reversal of 145430031224154 is 451422130034541.

It is a super-2 number, since 2×1454300312241542 (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52013600614 + ... + 52013603409.

It is an arithmetic number, because the mean of its divisors is an integer number (18256774306212).

Almost surely, 2145430031224154 is an apocalyptic number.

145430031224154 is an abundant number, since it is smaller than the sum of its proper divisors (146678357675238).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

145430031224154 is a wasteful number, since it uses less digits than its factorization.

145430031224154 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104027204261.

The product of its (nonzero) digits is 230400, while the sum is 39.

Adding to 145430031224154 its reverse (451422130034541), we get a palindrome (596852161258695).

The spelling of 145430031224154 in words is "one hundred forty-five trillion, four hundred thirty billion, thirty-one million, two hundred twenty-four thousand, one hundred fifty-four".

Divisors: 1 2 3 6 233 466 699 1398 104027204023 208054408046 312081612069 624163224138 24238338537359 48476677074718 72715015612077 145430031224154