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14544455001 = 34848151667
BaseRepresentation
bin11011000101110101…
…01100010101011001
31101112121221212102120
431202322230111121
5214241340030001
610403122051453
71023265553616
oct154272542531
941477855376
1014544455001
116193a6934a
12299aaa9b89
1314aa35a4bb
149bd92150d
155a1d2d236
hex362eac559

14544455001 has 4 divisors (see below), whose sum is σ = 19392606672. Its totient is φ = 9696303332.

The previous prime is 14544454931. The next prime is 14544455041. The reversal of 14544455001 is 10055444541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10055444541 = 33351814847.

It is a cyclic number.

It is not a de Polignac number, because 14544455001 - 211 = 14544452953 is a prime.

It is a super-2 number, since 2×145444550012 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14544455041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2424075831 + ... + 2424075836.

It is an arithmetic number, because the mean of its divisors is an integer number (4848151668).

Almost surely, 214544455001 is an apocalyptic number.

It is an amenable number.

14544455001 is a deficient number, since it is larger than the sum of its proper divisors (4848151671).

14544455001 is an equidigital number, since it uses as much as digits as its factorization.

14544455001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4848151670.

The product of its (nonzero) digits is 32000, while the sum is 33.

Adding to 14544455001 its reverse (10055444541), we get a palindrome (24599899542).

The spelling of 14544455001 in words is "fourteen billion, five hundred forty-four million, four hundred fifty-five thousand, one".

Divisors: 1 3 4848151667 14544455001