Base | Representation |
---|---|
bin | 100001000101010101100010… |
… | …000000001110110011100011 |
3 | 201002011212202001211000000211 |
4 | 201011111202000032303203 |
5 | 123032402102314030103 |
6 | 1233242451140154551 |
7 | 42435122266550464 |
oct | 4105254200166343 |
9 | 632155661730024 |
10 | 145502251314403 |
11 | 423a81816a4015 |
12 | 1439b389698a57 |
13 | 6325a5a17c819 |
14 | 27d04bcc90d6b |
15 | 11c4caa2e736d |
hex | 84556200ece3 |
145502251314403 has 4 divisors (see below), whose sum is σ = 145502516154528. Its totient is φ = 145501986474280.
The previous prime is 145502251314397. The next prime is 145502251314421. The reversal of 145502251314403 is 304413152205541.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 145502251314403 - 29 = 145502251313891 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (145502251314493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131594251 + ... + 132695332.
It is an arithmetic number, because the mean of its divisors is an integer number (36375629038632).
Almost surely, 2145502251314403 is an apocalyptic number.
145502251314403 is a deficient number, since it is larger than the sum of its proper divisors (264840125).
145502251314403 is an equidigital number, since it uses as much as digits as its factorization.
145502251314403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 264840124.
The product of its (nonzero) digits is 288000, while the sum is 40.
The spelling of 145502251314403 in words is "one hundred forty-five trillion, five hundred two billion, two hundred fifty-one million, three hundred fourteen thousand, four hundred three".
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