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145520034241 = 1163125124707
BaseRepresentation
bin1000011110000110101…
…0111000000111000001
3111220121112121200011211
42013201222320013001
54341011112043431
6150503451210121
713341056611411
oct2074152700701
9456545550154
10145520034241
11567952a160a
1224252446941
131095139b84a
1470867bc641
153bba64c2b1
hex21e1ab81c1

145520034241 has 4 divisors (see below), whose sum is σ = 145645160112. Its totient is φ = 145394908372.

The previous prime is 145520034239. The next prime is 145520034277. The reversal of 145520034241 is 142430025541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 145520034241 - 21 = 145520034239 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (145520038241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62561191 + ... + 62563516.

It is an arithmetic number, because the mean of its divisors is an integer number (36411290028).

Almost surely, 2145520034241 is an apocalyptic number.

It is an amenable number.

145520034241 is a deficient number, since it is larger than the sum of its proper divisors (125125871).

145520034241 is a wasteful number, since it uses less digits than its factorization.

145520034241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 125125870.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 145520034241 its reverse (142430025541), we get a palindrome (287950059782).

The spelling of 145520034241 in words is "one hundred forty-five billion, five hundred twenty million, thirty-four thousand, two hundred forty-one".

Divisors: 1 1163 125124707 145520034241