Base | Representation |
---|---|
bin | 100001000101100111010011… |
… | …110010100011010001110010 |
3 | 201002020201000101220212100112 |
4 | 201011213103302203101302 |
5 | 123033210201042400200 |
6 | 1233255325241221322 |
7 | 42436366316445353 |
oct | 4105472362432162 |
9 | 632221011825315 |
10 | 145521340200050 |
11 | 4240528789a371 |
12 | 143a3016491842 |
13 | 63277acb6bc29 |
14 | 27d13b0165d2a |
15 | 11c552608d535 |
hex | 8459d3ca3472 |
145521340200050 has 12 divisors (see below), whose sum is σ = 270669692772186. Its totient is φ = 58208536080000.
The previous prime is 145521340200023. The next prime is 145521340200059. The reversal of 145521340200050 is 50002043125541.
It can be written as a sum of positive squares in 3 ways, for example, as 139709870531449 + 5811469668601 = 11819893^2 + 2410699^2 .
It is not an unprimeable number, because it can be changed into a prime (145521340200059) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1455213401951 + ... + 1455213402050.
Almost surely, 2145521340200050 is an apocalyptic number.
145521340200050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
145521340200050 is a deficient number, since it is larger than the sum of its proper divisors (125148352572136).
145521340200050 is a wasteful number, since it uses less digits than its factorization.
145521340200050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2910426804013 (or 2910426804008 counting only the distinct ones).
The product of its (nonzero) digits is 24000, while the sum is 32.
Adding to 145521340200050 its reverse (50002043125541), we get a palindrome (195523383325591).
The spelling of 145521340200050 in words is "one hundred forty-five trillion, five hundred twenty-one billion, three hundred forty million, two hundred thousand, fifty".
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