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14552520120121 is a prime number
BaseRepresentation
bin1101001111000100010111…
…0010101101011100111001
31220112012121011000012112011
43103301011302231130321
53401412030122320441
650541200242445521
73031246005030604
oct323610562553471
956465534005464
1014552520120121
114700764251735
1217704616638a1
138173b1c96b79
143844ba98d33b
151a3827778581
hexd3c45cad739

14552520120121 has 2 divisors, whose sum is σ = 14552520120122. Its totient is φ = 14552520120120.

The previous prime is 14552520120097. The next prime is 14552520120137. The reversal of 14552520120121 is 12102102525541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12562516164496 + 1990003955625 = 3544364^2 + 1410675^2 .

It is a cyclic number.

It is not a de Polignac number, because 14552520120121 - 219 = 14552519595833 is a prime.

It is not a weakly prime, because it can be changed into another prime (14552520121121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7276260060060 + 7276260060061.

It is an arithmetic number, because the mean of its divisors is an integer number (7276260060061).

Almost surely, 214552520120121 is an apocalyptic number.

It is an amenable number.

14552520120121 is a deficient number, since it is larger than the sum of its proper divisors (1).

14552520120121 is an equidigital number, since it uses as much as digits as its factorization.

14552520120121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8000, while the sum is 31.

Adding to 14552520120121 its reverse (12102102525541), we get a palindrome (26654622645662).

The spelling of 14552520120121 in words is "fourteen trillion, five hundred fifty-two billion, five hundred twenty million, one hundred twenty thousand, one hundred twenty-one".