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145531241137 is a prime number
BaseRepresentation
bin1000011110001001010…
…1101000001010110001
3111220122022201001011001
42013202111220022301
54341021444204022
6150504531322001
713341254065522
oct2074225501261
9456568631131
10145531241137
11567a0656507
1224256150301
13109537c3849
147088098849
153bbb612b27
hex21e25682b1

145531241137 has 2 divisors, whose sum is σ = 145531241138. Its totient is φ = 145531241136.

The previous prime is 145531241117. The next prime is 145531241257. The reversal of 145531241137 is 731142135541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 142884756001 + 2646485136 = 378001^2 + 51444^2 .

It is an emirp because it is prime and its reverse (731142135541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 145531241137 - 223 = 145522852529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 145531241096 and 145531241105.

It is not a weakly prime, because it can be changed into another prime (145531241117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72765620568 + 72765620569.

It is an arithmetic number, because the mean of its divisors is an integer number (72765620569).

Almost surely, 2145531241137 is an apocalyptic number.

It is an amenable number.

145531241137 is a deficient number, since it is larger than the sum of its proper divisors (1).

145531241137 is an equidigital number, since it uses as much as digits as its factorization.

145531241137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 50400, while the sum is 37.

Adding to 145531241137 its reverse (731142135541), we get a palindrome (876673376678).

The spelling of 145531241137 in words is "one hundred forty-five billion, five hundred thirty-one million, two hundred forty-one thousand, one hundred thirty-seven".