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145541165101531 is a prime number
BaseRepresentation
bin100001000101111001110001…
…011100100011000111011011
3201002022121012000222012120221
4201011321301130203013123
5123034021301231222111
61233312404353500511
742441000514360063
oct4105716134430733
9632277160865527
10145541165101531
11424127304a4271
12143a6a29871737
13632961c19a974
1427d23310ac3a3
1511c5cd676d371
hex845e717231db

145541165101531 has 2 divisors, whose sum is σ = 145541165101532. Its totient is φ = 145541165101530.

The previous prime is 145541165101513. The next prime is 145541165101543. The reversal of 145541165101531 is 135101561145541.

145541165101531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (145541165101513) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 145541165101531 - 213 = 145541165093339 is a prime.

It is a super-2 number, since 2×1455411651015312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145541165101231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72770582550765 + 72770582550766.

It is an arithmetic number, because the mean of its divisors is an integer number (72770582550766).

Almost surely, 2145541165101531 is an apocalyptic number.

145541165101531 is a deficient number, since it is larger than the sum of its proper divisors (1).

145541165101531 is an equidigital number, since it uses as much as digits as its factorization.

145541165101531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180000, while the sum is 43.

The spelling of 145541165101531 in words is "one hundred forty-five trillion, five hundred forty-one billion, one hundred sixty-five million, one hundred one thousand, five hundred thirty-one".