Base | Representation |
---|---|
bin | 1000011110001110110… |
… | …0110101111101000011 |
3 | 111220200220201121021121 |
4 | 2013203230311331003 |
5 | 4341043322313011 |
6 | 150511105333111 |
7 | 13341652320502 |
oct | 2074354657503 |
9 | 456626647247 |
10 | 145554104131 |
11 | 56802551847 |
12 | 24261937197 |
13 | 1095846a147 |
14 | 708b12a839 |
15 | 3bbd62be71 |
hex | 21e3b35f43 |
145554104131 has 8 divisors (see below), whose sum is σ = 150952500720. Its totient is φ = 140180993568.
The previous prime is 145554104093. The next prime is 145554104147. The reversal of 145554104131 is 131401455541.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 145554104131 - 29 = 145554103619 is a prime.
It is a super-2 number, since 2×1455541041312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (145554101131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6309781 + ... + 6332806.
It is an arithmetic number, because the mean of its divisors is an integer number (18869062590).
Almost surely, 2145554104131 is an apocalyptic number.
145554104131 is a deficient number, since it is larger than the sum of its proper divisors (5398396589).
145554104131 is a wasteful number, since it uses less digits than its factorization.
145554104131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12643013.
The product of its (nonzero) digits is 24000, while the sum is 34.
Adding to 145554104131 its reverse (131401455541), we get a palindrome (276955559672).
The spelling of 145554104131 in words is "one hundred forty-five billion, five hundred fifty-four million, one hundred four thousand, one hundred thirty-one".
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