Base | Representation |
---|---|
bin | 1000011110011010101… |
… | …1010110110111111011 |
3 | 111220211101200221002201 |
4 | 2013212223112313323 |
5 | 4341144113440311 |
6 | 150520052011031 |
7 | 13343126654542 |
oct | 2074653266773 |
9 | 456741627081 |
10 | 145604046331 |
11 | 56828763097 |
12 | 24276600a77 |
13 | 10965905143 |
14 | 7093a0b159 |
15 | 3bc2be49c1 |
hex | 21e6ad6dfb |
145604046331 has 4 divisors (see below), whose sum is σ = 145604965792. Its totient is φ = 145603126872.
The previous prime is 145604046311. The next prime is 145604046349. The reversal of 145604046331 is 133640406541.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 133640406541 = 1049 ⋅127397909.
It is a cyclic number.
It is not a de Polignac number, because 145604046331 - 25 = 145604046299 is a prime.
It is a super-2 number, since 2×1456040463312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (145604046311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 154755 + ... + 561388.
It is an arithmetic number, because the mean of its divisors is an integer number (36401241448).
Almost surely, 2145604046331 is an apocalyptic number.
145604046331 is a deficient number, since it is larger than the sum of its proper divisors (919461).
145604046331 is an equidigital number, since it uses as much as digits as its factorization.
145604046331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 919460.
The product of its (nonzero) digits is 103680, while the sum is 37.
The spelling of 145604046331 in words is "one hundred forty-five billion, six hundred four million, forty-six thousand, three hundred thirty-one".
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