Search a number
-
+
145645023434 = 272822511717
BaseRepresentation
bin1000011110100100011…
…1101011000011001010
3111220221020210210010012
42013221013223003022
54341240111222214
6150524114151522
713344135162401
oct2075107530312
9456836723105
10145645023434
1156849900869
12242882825a2
1310971251651
147099236638
153bc65db03e
hex21e91eb0ca

145645023434 has 4 divisors (see below), whose sum is σ = 218467535154. Its totient is φ = 72822511716.

The previous prime is 145645023427. The next prime is 145645023437. The reversal of 145645023434 is 434320546541.

145645023434 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 118884971209 + 26760052225 = 344797^2 + 163585^2 .

It is a junction number, because it is equal to n+sod(n) for n = 145645023391 and 145645023400.

It is not an unprimeable number, because it can be changed into a prime (145645023437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36411255857 + ... + 36411255860.

Almost surely, 2145645023434 is an apocalyptic number.

145645023434 is a deficient number, since it is larger than the sum of its proper divisors (72822511720).

145645023434 is an equidigital number, since it uses as much as digits as its factorization.

145645023434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72822511719.

The product of its (nonzero) digits is 691200, while the sum is 41.

Adding to 145645023434 its reverse (434320546541), we get a palindrome (579965569975).

The spelling of 145645023434 in words is "one hundred forty-five billion, six hundred forty-five million, twenty-three thousand, four hundred thirty-four".

Divisors: 1 2 72822511717 145645023434