Base | Representation |
---|---|
bin | 11011001011010100… |
… | …00101000011001001 |
3 | 1101122211110201020101 |
4 | 31211222011003021 |
5 | 214340122301213 |
6 | 10411443325401 |
7 | 1024364422654 |
oct | 154552050311 |
9 | 41584421211 |
10 | 14590431433 |
11 | 6207a110a6 |
12 | 29b2380861 |
13 | 14b6a373a6 |
14 | 9c5a8c89b |
15 | 5a5db0bdd |
hex | 365a850c9 |
14590431433 has 2 divisors, whose sum is σ = 14590431434. Its totient is φ = 14590431432.
The previous prime is 14590431403. The next prime is 14590431439. The reversal of 14590431433 is 33413409541.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14345571529 + 244859904 = 119773^2 + 15648^2 .
It is a cyclic number.
It is not a de Polignac number, because 14590431433 - 213 = 14590423241 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14590431392 and 14590431401.
It is not a weakly prime, because it can be changed into another prime (14590431439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7295215716 + 7295215717.
It is an arithmetic number, because the mean of its divisors is an integer number (7295215717).
Almost surely, 214590431433 is an apocalyptic number.
It is an amenable number.
14590431433 is a deficient number, since it is larger than the sum of its proper divisors (1).
14590431433 is an equidigital number, since it uses as much as digits as its factorization.
14590431433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 37.
The spelling of 14590431433 in words is "fourteen billion, five hundred ninety million, four hundred thirty-one thousand, four hundred thirty-three".
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