Search a number
-
+
14593184953 is a prime number
BaseRepresentation
bin11011001011101001…
…00101010010111001
31101200000122121100121
431211310211102321
5214341323404303
610412022333241
71024430011504
oct154564452271
941600577317
1014593184953
116209521936
1229b328a221
1314b748c7a9
149c61a813b
155a62569bd
hex365d254b9

14593184953 has 2 divisors, whose sum is σ = 14593184954. Its totient is φ = 14593184952.

The previous prime is 14593184927. The next prime is 14593184971. The reversal of 14593184953 is 35948139541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14353956864 + 239228089 = 119808^2 + 15467^2 .

It is an emirp because it is prime and its reverse (35948139541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14593184953 - 225 = 14559630521 is a prime.

It is a super-3 number, since 3×145931849533 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 14593184953.

It is not a weakly prime, because it can be changed into another prime (14593134953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7296592476 + 7296592477.

It is an arithmetic number, because the mean of its divisors is an integer number (7296592477).

Almost surely, 214593184953 is an apocalyptic number.

It is an amenable number.

14593184953 is a deficient number, since it is larger than the sum of its proper divisors (1).

14593184953 is an equidigital number, since it uses as much as digits as its factorization.

14593184953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2332800, while the sum is 52.

The spelling of 14593184953 in words is "fourteen billion, five hundred ninety-three million, one hundred eighty-four thousand, nine hundred fifty-three".