Base | Representation |
---|---|
bin | 10101001111110000011… |
… | …111100110111110010001 |
3 | 12011120120220122022010121 |
4 | 111033300133212332101 |
5 | 142410114323400111 |
6 | 3034421122430241 |
7 | 210324605310301 |
oct | 25176037467621 |
9 | 5146526568117 |
10 | 1460028731281 |
11 | 51321617960a |
12 | 1b6b68802381 |
13 | a78ac2b3703 |
14 | 50946c1b601 |
15 | 27ea318a871 |
hex | 153f07e6f91 |
1460028731281 has 2 divisors, whose sum is σ = 1460028731282. Its totient is φ = 1460028731280.
The previous prime is 1460028731209. The next prime is 1460028731333. The reversal of 1460028731281 is 1821378200641.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 976225017681 + 483803713600 = 988041^2 + 695560^2 .
It is a cyclic number.
It is not a de Polignac number, because 1460028731281 - 213 = 1460028723089 is a prime.
It is a super-2 number, since 2×14600287312812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1460028737281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 730014365640 + 730014365641.
It is an arithmetic number, because the mean of its divisors is an integer number (730014365641).
Almost surely, 21460028731281 is an apocalyptic number.
It is an amenable number.
1460028731281 is a deficient number, since it is larger than the sum of its proper divisors (1).
1460028731281 is an equidigital number, since it uses as much as digits as its factorization.
1460028731281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129024, while the sum is 43.
The spelling of 1460028731281 in words is "one trillion, four hundred sixty billion, twenty-eight million, seven hundred thirty-one thousand, two hundred eighty-one".
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