Base | Representation |
---|---|
bin | 1101010011010000001000… |
… | …1100101110011001110011 |
3 | 1220210002010121200112002011 |
4 | 3110310002030232121303 |
5 | 3404101233014024412 |
6 | 51034205025303351 |
7 | 3036402164331061 |
oct | 324640214563163 |
9 | 56702117615064 |
10 | 14624400533107 |
11 | 472919a930922 |
12 | 1782382194b57 |
13 | 8210c8b77911 |
14 | 387b79211031 |
15 | 1a5632ec87a7 |
hex | d4d0232e673 |
14624400533107 has 2 divisors, whose sum is σ = 14624400533108. Its totient is φ = 14624400533106.
The previous prime is 14624400532949. The next prime is 14624400533129. The reversal of 14624400533107 is 70133500442641.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14624400533107 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14624400533107.
It is not a weakly prime, because it can be changed into another prime (14624400533137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7312200266553 + 7312200266554.
It is an arithmetic number, because the mean of its divisors is an integer number (7312200266554).
Almost surely, 214624400533107 is an apocalyptic number.
14624400533107 is a deficient number, since it is larger than the sum of its proper divisors (1).
14624400533107 is an equidigital number, since it uses as much as digits as its factorization.
14624400533107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 241920, while the sum is 40.
Adding to 14624400533107 its reverse (70133500442641), we get a palindrome (84757900975748).
The spelling of 14624400533107 in words is "fourteen trillion, six hundred twenty-four billion, four hundred million, five hundred thirty-three thousand, one hundred seven".
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