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146261420221051 is a prime number
BaseRepresentation
bin100001010000011000100011…
…111111110010001001111011
3201011212110021212001021202201
4201100120203333302021323
5123132321342034033201
61235023322512411031
742544016225024152
oct4120304377621173
9634773255037681
10146261420221051
1142670135761a63
12144a2539846a77
13637c514b28215
14281913a508599
1511d98ddb87801
hex850623ff227b

146261420221051 has 2 divisors, whose sum is σ = 146261420221052. Its totient is φ = 146261420221050.

The previous prime is 146261420220997. The next prime is 146261420221057. The reversal of 146261420221051 is 150122024162641.

146261420221051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 146261420221051 - 223 = 146261411832443 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 146261420221051.

It is not a weakly prime, because it can be changed into another prime (146261420221057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73130710110525 + 73130710110526.

It is an arithmetic number, because the mean of its divisors is an integer number (73130710110526).

Almost surely, 2146261420221051 is an apocalyptic number.

146261420221051 is a deficient number, since it is larger than the sum of its proper divisors (1).

146261420221051 is an equidigital number, since it uses as much as digits as its factorization.

146261420221051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46080, while the sum is 37.

Adding to 146261420221051 its reverse (150122024162641), we get a palindrome (296383444383692).

The spelling of 146261420221051 in words is "one hundred forty-six trillion, two hundred sixty-one billion, four hundred twenty million, two hundred twenty-one thousand, fifty-one".