Base | Representation |
---|---|
bin | 1101010100010110010101… |
… | …0111101111011110010001 |
3 | 1220211212202212102202000210 |
4 | 3111011211113233132101 |
5 | 3404403331011002031 |
6 | 51051002531234333 |
7 | 3040640146212321 |
oct | 325054527573621 |
9 | 56755685382023 |
10 | 14643244234641 |
11 | 473618a692780 |
12 | 1785b60a489a9 |
13 | 822b0cb1c679 |
14 | 388a45b01281 |
15 | 1a5d8748c746 |
hex | d51655ef791 |
14643244234641 has 16 divisors (see below), whose sum is σ = 21874920136128. Its totient is φ = 8634836894400.
The previous prime is 14643244234547. The next prime is 14643244234693.
14643244234641 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 14643244234641 - 213 = 14643244226449 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14643244238641) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5996413290 + ... + 5996415731.
It is an arithmetic number, because the mean of its divisors is an integer number (1367182508508).
Almost surely, 214643244234641 is an apocalyptic number.
14643244234641 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
14643244234641 is a deficient number, since it is larger than the sum of its proper divisors (7231675901487).
14643244234641 is a wasteful number, since it uses less digits than its factorization.
14643244234641 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11992829072.
The product of its digits is 5308416, while the sum is 48.
It can be divided in two parts, 1464324 and 4234641, that added together give a palindrome (5698965).
The spelling of 14643244234641 in words is "fourteen trillion, six hundred forty-three billion, two hundred forty-four million, two hundred thirty-four thousand, six hundred forty-one".
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