Base | Representation |
---|---|
bin | 1101010100101101001110… |
… | …0111011100100000011001 |
3 | 1220212110122002112121222121 |
4 | 3111023103213130200121 |
5 | 3410003422013443223 |
6 | 51053500351021241 |
7 | 3041245340235043 |
oct | 325132347344031 |
9 | 56773562477877 |
10 | 14649388812313 |
11 | 4738853091942 |
12 | 178719680a821 |
13 | 82357bb39248 |
14 | 389069bc6a93 |
15 | 1a60e6b3315d |
hex | d52d39dc819 |
14649388812313 has 2 divisors, whose sum is σ = 14649388812314. Its totient is φ = 14649388812312.
The previous prime is 14649388812263. The next prime is 14649388812319. The reversal of 14649388812313 is 31321888394641.
14649388812313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14649388812304 + 9 = 3827452^2 + 3^2 .
It is a cyclic number.
It is not a de Polignac number, because 14649388812313 - 217 = 14649388681241 is a prime.
It is not a weakly prime, because it can be changed into another prime (14649388812319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7324694406156 + 7324694406157.
It is an arithmetic number, because the mean of its divisors is an integer number (7324694406157).
Almost surely, 214649388812313 is an apocalyptic number.
It is an amenable number.
14649388812313 is a deficient number, since it is larger than the sum of its proper divisors (1).
14649388812313 is an equidigital number, since it uses as much as digits as its factorization.
14649388812313 is an evil number, because the sum of its binary digits is even.
The product of its digits is 23887872, while the sum is 61.
The spelling of 14649388812313 in words is "fourteen trillion, six hundred forty-nine billion, three hundred eighty-eight million, eight hundred twelve thousand, three hundred thirteen".
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