1465112230243 has 4 divisors (see below), whose sum is σ = 1465313020360. Its totient is φ = 1464911440128.

The previous prime is 1465112230217. The next prime is 1465112230261. The reversal of 1465112230243 is 3420322115641.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1465112230243 - 2⁹ = 1465112229731 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1465112230199 and 1465112230208.

It is not an unprimeable number, because it can be changed into a prime (1465112230213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100384113 + ... + 100398706.

It is an arithmetic number, because the mean of its divisors is an integer number (366328255090).

Almost surely, 2^{1465112230243} is an apocalyptic number.

1465112230243 is a deficient number, since it is larger than the sum of its proper divisors (200790117).

1465112230243 is an equidigital number, since it uses as much as digits as its factorization.

1465112230243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 200790116.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 1465112230243 its reverse (3420322115641), we get a palindrome (4885434345884).

The spelling of 1465112230243 in words is "one trillion, four hundred sixty-five billion, one hundred twelve million, two hundred thirty thousand, two hundred forty-three".