Base | Representation |
---|---|
bin | 1000100001111100001… |
… | …0011100000110001011 |
3 | 112000021021222002212121 |
4 | 2020133002130012023 |
5 | 4400113200334011 |
6 | 151153550552111 |
7 | 13405431140434 |
oct | 2103702340613 |
9 | 460237862777 |
10 | 146549621131 |
11 | 57173493471 |
12 | 2449b208637 |
13 | 10a86797964 |
14 | 714342c48b |
15 | 3c2ac24e71 |
hex | 221f09c18b |
146549621131 has 2 divisors, whose sum is σ = 146549621132. Its totient is φ = 146549621130.
The previous prime is 146549621087. The next prime is 146549621137. The reversal of 146549621131 is 131126945641.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-146549621131 is a prime.
It is a super-2 number, since 2×1465496211312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (146549621137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 73274810565 + 73274810566.
It is an arithmetic number, because the mean of its divisors is an integer number (73274810566).
Almost surely, 2146549621131 is an apocalyptic number.
146549621131 is a deficient number, since it is larger than the sum of its proper divisors (1).
146549621131 is an equidigital number, since it uses as much as digits as its factorization.
146549621131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 155520, while the sum is 43.
The spelling of 146549621131 in words is "one hundred forty-six billion, five hundred forty-nine million, six hundred twenty-one thousand, one hundred thirty-one".
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