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1466102113 = 7209443159
BaseRepresentation
bin101011101100010…
…1111000101100001
310210011201201000021
41113120233011201
511000310231423
6401251353441
751221443120
oct12730570541
93704651007
101466102113
11692638243
1234abb2881
131a4984058
14dc9dbab7
1588aa095d
hex5762f161

1466102113 has 4 divisors (see below), whose sum is σ = 1675545280. Its totient is φ = 1256658948.

The previous prime is 1466102101. The next prime is 1466102129. The reversal of 1466102113 is 3112016641.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1466102113 - 25 = 1466102081 is a prime.

It is a super-3 number, since 3×14661021133 (a number of 28 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1466102713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 104721573 + ... + 104721586.

It is an arithmetic number, because the mean of its divisors is an integer number (418886320).

Almost surely, 21466102113 is an apocalyptic number.

It is an amenable number.

1466102113 is a deficient number, since it is larger than the sum of its proper divisors (209443167).

1466102113 is an equidigital number, since it uses as much as digits as its factorization.

1466102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 209443166.

The product of its (nonzero) digits is 864, while the sum is 25.

The square root of 1466102113 is about 38289.7128874062. The cubic root of 1466102113 is about 1136.0254823951.

Adding to 1466102113 its reverse (3112016641), we get a palindrome (4578118754).

The spelling of 1466102113 in words is "one billion, four hundred sixty-six million, one hundred two thousand, one hundred thirteen".

Divisors: 1 7 209443159 1466102113