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1466813481433 is a prime number
BaseRepresentation
bin10101010110000100111…
…001011000000111011001
312012020002202100022122021
4111112010321120013121
5143013013222401213
63041502251254441
7210655001606056
oct25260471300731
95166082308567
101466813481433
11516087a74843
121b8340a4a421
13a8420b23081
1450dcbd4602d
152824db36d8d
hex15584e581d9

1466813481433 has 2 divisors, whose sum is σ = 1466813481434. Its totient is φ = 1466813481432.

The previous prime is 1466813481407. The next prime is 1466813481479. The reversal of 1466813481433 is 3341843186641.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1466780165449 + 33315984 = 1211107^2 + 5772^2 .

It is a cyclic number.

It is not a de Polignac number, because 1466813481433 - 221 = 1466811384281 is a prime.

It is not a weakly prime, because it can be changed into another prime (1466813485433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 733406740716 + 733406740717.

It is an arithmetic number, because the mean of its divisors is an integer number (733406740717).

Almost surely, 21466813481433 is an apocalyptic number.

It is an amenable number.

1466813481433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1466813481433 is an equidigital number, since it uses as much as digits as its factorization.

1466813481433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3981312, while the sum is 52.

The spelling of 1466813481433 in words is "one trillion, four hundred sixty-six billion, eight hundred thirteen million, four hundred eighty-one thousand, four hundred thirty-three".