Base | Representation |
---|---|
bin | 11011011001111111… |
… | …00001101011001001 |
3 | 1101222102000221122021 |
4 | 31230333201223021 |
5 | 220113123303332 |
6 | 10432001124441 |
7 | 1030420431412 |
oct | 155477415311 |
9 | 41872027567 |
10 | 14713494217 |
11 | 6270424a84 |
12 | 2a27629721 |
13 | 15063943c6 |
14 | 9d8164809 |
15 | 5b1abdc97 |
hex | 36cfe1ac9 |
14713494217 has 2 divisors, whose sum is σ = 14713494218. Its totient is φ = 14713494216.
The previous prime is 14713494181. The next prime is 14713494221. The reversal of 14713494217 is 71249431741.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13761401481 + 952092736 = 117309^2 + 30856^2 .
It is an emirp because it is prime and its reverse (71249431741) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14713494217 - 223 = 14705105609 is a prime.
It is not a weakly prime, because it can be changed into another prime (14713494617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7356747108 + 7356747109.
It is an arithmetic number, because the mean of its divisors is an integer number (7356747109).
Almost surely, 214713494217 is an apocalyptic number.
It is an amenable number.
14713494217 is a deficient number, since it is larger than the sum of its proper divisors (1).
14713494217 is an equidigital number, since it uses as much as digits as its factorization.
14713494217 is an evil number, because the sum of its binary digits is even.
The product of its digits is 169344, while the sum is 43.
The spelling of 14713494217 in words is "fourteen billion, seven hundred thirteen million, four hundred ninety-four thousand, two hundred seventeen".
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