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14718890473 = 72102698639
BaseRepresentation
bin11011011010101000…
…00111000111101001
31101222210012002220121
431231110013013221
5220121013443343
610432312523241
71030514335060
oct155524070751
941883162817
1014718890473
1162734802a1
122a293b0521
131507533661
149d8b6b1d7
155b22d7aed
hex36d5071e9

14718890473 has 4 divisors (see below), whose sum is σ = 16821589120. Its totient is φ = 12616191828.

The previous prime is 14718890449. The next prime is 14718890603. The reversal of 14718890473 is 37409881741.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14718890473 - 25 = 14718890441 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14718890473.

It is not an unprimeable number, because it can be changed into a prime (14718890443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1051349313 + ... + 1051349326.

It is an arithmetic number, because the mean of its divisors is an integer number (4205397280).

Almost surely, 214718890473 is an apocalyptic number.

It is an amenable number.

14718890473 is a deficient number, since it is larger than the sum of its proper divisors (2102698647).

14718890473 is an equidigital number, since it uses as much as digits as its factorization.

14718890473 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2102698646.

The product of its (nonzero) digits is 1354752, while the sum is 52.

The spelling of 14718890473 in words is "fourteen billion, seven hundred eighteen million, eight hundred ninety thousand, four hundred seventy-three".

Divisors: 1 7 2102698639 14718890473