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1473061312553 is a prime number
BaseRepresentation
bin10101011011111001010…
…010111101100000101001
312012211020011202000200212
4111123321102331200221
5143113312144000203
63044414240110505
7211265555364125
oct25337122754051
95184204660625
101473061312553
115187a3787836
121b95a5305435
13a8ba835226c
1451421a28585
15284b73c61d8
hex156f94bd829

1473061312553 has 2 divisors, whose sum is σ = 1473061312554. Its totient is φ = 1473061312552.

The previous prime is 1473061312519. The next prime is 1473061312607. The reversal of 1473061312553 is 3552131603741.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1236016968169 + 237044344384 = 1111763^2 + 486872^2 .

It is a cyclic number.

It is not a de Polignac number, because 1473061312553 - 28 = 1473061312297 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1473061312553.

It is not a weakly prime, because it can be changed into another prime (1473061312153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 736530656276 + 736530656277.

It is an arithmetic number, because the mean of its divisors is an integer number (736530656277).

Almost surely, 21473061312553 is an apocalyptic number.

It is an amenable number.

1473061312553 is a deficient number, since it is larger than the sum of its proper divisors (1).

1473061312553 is an equidigital number, since it uses as much as digits as its factorization.

1473061312553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 226800, while the sum is 41.

The spelling of 1473061312553 in words is "one trillion, four hundred seventy-three billion, sixty-one million, three hundred twelve thousand, five hundred fifty-three".