1473653336417 has 2 divisors, whose sum is σ = 1473653336418. Its totient is φ = 1473653336416.

The previous prime is 1473653336321. The next prime is 1473653336447. The reversal of 1473653336417 is 7146333563741.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1233008147281 + 240645189136 = 1110409^2 + 490556^2 .

It is a cyclic number.

It is not a de Polignac number, because 1473653336417 - 2¹⁸ = 1473653074273 is a prime.

It is a super-4 number, since 4×1473653336417⁴ (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.

It is not a weakly prime, because it can be changed into another prime (1473653336447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 736826668208 + 736826668209.

It is an arithmetic number, because the mean of its divisors is an integer number (736826668209).

Almost surely, 2^{1473653336417} is an apocalyptic number.

It is an amenable number.

1473653336417 is a deficient number, since it is larger than the sum of its proper divisors (1).

1473653336417 is an equidigital number, since it uses as much as digits as its factorization.

1473653336417 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11430720, while the sum is 53.

The spelling of 1473653336417 in words is "one trillion, four hundred seventy-three billion, six hundred fifty-three million, three hundred thirty-six thousand, four hundred seventeen".