Base | Representation |
---|---|
bin | 11011011101011010… |
… | …01111000110110011 |
3 | 1102001102011002122112 |
4 | 31232231033012303 |
5 | 220143004112003 |
6 | 10434505355535 |
7 | 1031220043241 |
oct | 155655170663 |
9 | 42042132575 |
10 | 14742254003 |
11 | 62856886a4 |
12 | 2a35198bab |
13 | 150c323a29 |
14 | 9dbccd791 |
15 | 5b43a03d8 |
hex | 36eb4f1b3 |
14742254003 has 2 divisors, whose sum is σ = 14742254004. Its totient is φ = 14742254002.
The previous prime is 14742253997. The next prime is 14742254017. The reversal of 14742254003 is 30045224741.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14742254003 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (14742254053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7371127001 + 7371127002.
It is an arithmetic number, because the mean of its divisors is an integer number (7371127002).
Almost surely, 214742254003 is an apocalyptic number.
14742254003 is a deficient number, since it is larger than the sum of its proper divisors (1).
14742254003 is an equidigital number, since it uses as much as digits as its factorization.
14742254003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26880, while the sum is 32.
Adding to 14742254003 its reverse (30045224741), we get a palindrome (44787478744).
The spelling of 14742254003 in words is "fourteen billion, seven hundred forty-two million, two hundred fifty-four thousand, three".
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