Base | Representation |
---|---|
bin | 10101011101001001010… |
… | …010110000100010101001 |
3 | 12012221200201011222221002 |
4 | 111131021102300202221 |
5 | 143124034234433323 |
6 | 3045155342324345 |
7 | 211344043300424 |
oct | 25351122604251 |
9 | 5187621158832 |
10 | 1474403436713 |
11 | 519322336559 |
12 | 1b98ba8896b5 |
13 | a906041887c |
14 | 5150bd929bb |
15 | 28545137828 |
hex | 157494b08a9 |
1474403436713 has 2 divisors, whose sum is σ = 1474403436714. Its totient is φ = 1474403436712.
The previous prime is 1474403436683. The next prime is 1474403436767. The reversal of 1474403436713 is 3176343044741.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 917748672064 + 556654764649 = 957992^2 + 746093^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1474403436713 is a prime.
It is a super-2 number, since 2×14744034367132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1474403438713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 737201718356 + 737201718357.
It is an arithmetic number, because the mean of its divisors is an integer number (737201718357).
Almost surely, 21474403436713 is an apocalyptic number.
It is an amenable number.
1474403436713 is a deficient number, since it is larger than the sum of its proper divisors (1).
1474403436713 is an equidigital number, since it uses as much as digits as its factorization.
1474403436713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2032128, while the sum is 47.
The spelling of 1474403436713 in words is "one trillion, four hundred seventy-four billion, four hundred three million, four hundred thirty-six thousand, seven hundred thirteen".
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