Base | Representation |
---|---|
bin | 1000100111110000110… |
… | …1001000110110111011 |
3 | 112011022020012002120221 |
4 | 2021330031020312323 |
5 | 4411313323111003 |
6 | 152013025200511 |
7 | 13462241144212 |
oct | 2117415106673 |
9 | 464266162527 |
10 | 148112707003 |
11 | 578a5841a78 |
12 | 24856790137 |
13 | 10c75577641 |
14 | 7250c74079 |
15 | 3cbd0817bd |
hex | 227c348dbb |
148112707003 has 2 divisors, whose sum is σ = 148112707004. Its totient is φ = 148112707002.
The previous prime is 148112706983. The next prime is 148112707019. The reversal of 148112707003 is 300707211841.
It is a strong prime.
It is an emirp because it is prime and its reverse (300707211841) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 148112707003 - 217 = 148112575931 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 148112707003.
It is not a weakly prime, because it can be changed into another prime (148112707033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74056353501 + 74056353502.
It is an arithmetic number, because the mean of its divisors is an integer number (74056353502).
Almost surely, 2148112707003 is an apocalyptic number.
148112707003 is a deficient number, since it is larger than the sum of its proper divisors (1).
148112707003 is an equidigital number, since it uses as much as digits as its factorization.
148112707003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9408, while the sum is 34.
Adding to 148112707003 its reverse (300707211841), we get a palindrome (448819918844).
The spelling of 148112707003 in words is "one hundred forty-eight billion, one hundred twelve million, seven hundred seven thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •