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148142839681 is a prime number
BaseRepresentation
bin1000100111111000000…
…0000101011110000001
3112011101022212222212001
42021332000011132001
54411344031332211
6152020023104001
713463055234454
oct2117600053601
9464338788761
10148142839681
1157910853111
12248648a2001
1310c7b897b25
147254c7949b
153cc0a34ac1
hex227e005781

148142839681 has 2 divisors, whose sum is σ = 148142839682. Its totient is φ = 148142839680.

The previous prime is 148142839639. The next prime is 148142839703. The reversal of 148142839681 is 186938241841.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80914647025 + 67228192656 = 284455^2 + 259284^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-148142839681 is a prime.

It is a super-2 number, since 2×1481428396812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (148142839181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 74071419840 + 74071419841.

It is an arithmetic number, because the mean of its divisors is an integer number (74071419841).

Almost surely, 2148142839681 is an apocalyptic number.

It is an amenable number.

148142839681 is a deficient number, since it is larger than the sum of its proper divisors (1).

148142839681 is an equidigital number, since it uses as much as digits as its factorization.

148142839681 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2654208, while the sum is 55.

The spelling of 148142839681 in words is "one hundred forty-eight billion, one hundred forty-two million, eight hundred thirty-nine thousand, six hundred eighty-one".